Subject: RE: [xsl] compare two lists of values question From: "Robert C. Lyons" <boblyons@xxxxxxxxxx> Date: Tue, 7 Aug 2001 21:55:05 -0400 |
Hal, The following stylesheet should do the trick: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text"/> <xsl:key name="us_merchants" match="USMerchants/name" use="."/> <xsl:key name="uk_merchants" match="UKMerchants/name" use="."/> <xsl:template match="/"> <xsl:for-each select="/Merchants/*/name"> <xsl:if test="( key( 'us_merchants', . ) and not( key( 'uk_merchants', . ) ) ) or ( key( 'uk_merchants', . ) and not( key( 'us_merchants', . ) ) )"> <xsl:value-of select="."/> <xsl:text> is not in both lists.
</xsl:text> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> Please note that I changed the name of the UKMerchant element to "UKMerchants". Hope this helps. Bob <sig name = 'Bob Lyons' title = 'XML Consultant' company = 'Unidex, Inc.' phone = '+1-732-975-9877' email = 'boblyons@xxxxxxxxxx' url = 'http://www.unidex.com/' product = 'XML Convert: transforms flat files to XML and vice versa' /> -----Original Message----- I'm assuming this is kind of a novice level question. I need to compare two lists of values and display the value of any name element not in both lists. The xml is like this: <Merchants> <USMerchants> <name>store1</name> <name>store2</name> <name>store3</name> <name>store4</name> <name>store5</name> <name>store6</name> </USMerchants> <UKMerchant> <name>store1</name> <name>store2</name> <name>store3</name> <name>store4</name> <name>store5</name> <name>store99</name> </UKMerchant> </Merchants> Using MSXML3 parser. Thanks in advance, Hal Friedlander XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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