[xsl] Re: compare two lists of values question

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

Friedlander, Hal wrote:

> I need to compare two lists of values and display the value of any name
> element not in both lists.
> The xml is like this:
> <Merchants>
> <USMerchants>
> 	<name>store1</name>
> 	<name>store2</name>
> 	<name>store3</name>
> 	<name>store4</name>
> 	<name>store5</name>
> 	<name>store6</name>
> </USMerchants>
> <UKMerchant>
> 	<name>store1</name>
> 	<name>store2</name>
> 	<name>store3</name>
> 	<name>store4</name>
> 	<name>store5</name>
> 	<name>store99</name>
> </UKMerchant>
> </Merchants>

Hi Hal,

Assumng that a name cannot appear more than once in a list (which seems to be your
case), then a simple way to achieve the desired result is as follows:

<xsl:key name="kName" match="name" use="."/>

Using the above xsl:key, the following XPath expression returns a node-set of all
names that appear only once (and therefore only in one of the lists).

/Merchants/*/name[count(key('kName', .)) = 1]

Hope this helped.

Cheers,
Dimitre Novatchev.

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