Subject: Re: [xsl] apostrophe in paramter causing output problems From: Mike Brown <mike@xxxxxxxx> Date: Wed, 15 Aug 2001 12:52:05 -0600 (MDT) |
Uronis, Jeremy wrote: > translate($Description,"'","\'")} Instead of "'", declare a variable like this: <xsl:variable name="q">'</xsl:variable> and then use $q. However you have a bigger problem in that you misunderstand how translate() works. It works like the Unix 'tr' utility -- it only replaces single characters. You need a recursive template to do arbitrary string replacement. See http://skew.org/xml/stylesheets/replace/ for one such example. You'll do this: <xsl:call-template name="SubstringReplace"> <xsl:with-param name="stringIn" select="$Description" /> <xsl:with-param name="substringIn">'</xsl:with-param> <xsl:with-param name="substringOut">\'</xsl:with-param> </xsl:call-template> - Mike ____________________________________________________________________________ mike j. brown, fourthought.com | xml/xslt: http://skew.org/xml/ denver/boulder, colorado, usa | personal: http://hyperreal.org/~mike/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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