Subject: Re: [xsl]xpath for getting file version From: "Antony Suryadinata" <antodinata@xxxxxxxxxxx> Date: Thu, 16 Aug 2001 10:18:14 +1000 |
Re: [xsl]xpath for getting file versionThank you Jeni for the suggestions and Dimitre for the generic template. Jeni wrote: > Second, you could have a two-stage process (either with two > stylesheets or using a node-set() extension function to do it all in > one stylesheet). In the first pass, construct XML like the above, with > a date attribute giving the entire date, and then use the XPath above > in the key. If I use the second suggestion using the node-set() extension function, how would I use the <xsl:key>? Say if I put my modified XML into a variable called "temp". <xsl:variable name="modified" select="xalan:nodeset($temp)"/> <xsl:key name="maxfile" match="$modified/person" use="versions/version[not(@date < ../version/@date)]/@name"/> Is that how? Thank you for your help, Antony XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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