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Subject: [xsl] URL variables From: "John Bougie" <jbougie@xxxxxxxxxx> Date: Thu, 16 Aug 2001 11:56:31 -0400 |
Hi,
I am trying to do something sounds really simple but can't seem to get
it going. Here is what I am doing. I have a HTML form that looks something
like this:
<html>
<body>
<form method="get" action="testPage">
<table>
<tr>
<td>ID# :</td>
<td><input type="text" name="id1" value=""></input></td>
<td>
<input type="submit" value="Submit Query" name="submit"></input>
</tr>
</table>
</form>
</body>
</html>
That will post and call and xsl file with a URL that looks like this:
https://localhost/testPage?id1=A&submit=Submit+Query
In the full version of the file, not the trimmed down one above the page
get called with the proper URL and is rendered, for the most part fine.
What I want to do in the XSL sheet that is not working is print the value
of ID which is in the URL. This is an abbreviated version of the XSL
sheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
<xsl:param name="id" select="."/>
<html>
<body>
THE ID ENTERED IS : <xsl:value-of select="$id"/>
</body>
</html>
</xsl:output>
</xsl:stylesheet>
It was my understanding that in order to get a variable from the URL
you need to do a <xsl:param name="id" select="."/> before your first
template call and then inside a template to access it (i.e. print the
value) you would need to do a <xsl:value-of select="$id"/>. Can anyone
tell me if I am one the right track, or am I way off the mark.
Thanks
John
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