Subject: [xsl] URL variables From: "John Bougie" <jbougie@xxxxxxxxxx> Date: Thu, 16 Aug 2001 11:56:31 -0400 |
Hi, I am trying to do something sounds really simple but can't seem to get it going. Here is what I am doing. I have a HTML form that looks something like this: <html> <body> <form method="get" action="testPage"> <table> <tr> <td>ID# :</td> <td><input type="text" name="id1" value=""></input></td> <td> <input type="submit" value="Submit Query" name="submit"></input> </tr> </table> </form> </body> </html> That will post and call and xsl file with a URL that looks like this: https://localhost/testPage?id1=A&submit=Submit+Query In the full version of the file, not the trimmed down one above the page get called with the proper URL and is rendered, for the most part fine. What I want to do in the XSL sheet that is not working is print the value of ID which is in the URL. This is an abbreviated version of the XSL sheet: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html"/> <xsl:param name="id" select="."/> <html> <body> THE ID ENTERED IS : <xsl:value-of select="$id"/> </body> </html> </xsl:output> </xsl:stylesheet> It was my understanding that in order to get a variable from the URL you need to do a <xsl:param name="id" select="."/> before your first template call and then inside a template to access it (i.e. print the value) you would need to do a <xsl:value-of select="$id"/>. Can anyone tell me if I am one the right track, or am I way off the mark. Thanks John __________________________________________________ FREE voicemail, email, and fax...all in one place. Sign Up Now! http://www.onebox.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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