Subject: RE: [xsl] get the name of a node which I know the value From: "KIENLE, STEVEN C [IT/0200]" <steven.c.kienle@xxxxxxxxxxxxx> Date: Tue, 21 Aug 2001 06:51:57 -0500 |
I think what you want is something like: <xsl:variable name="CurrentFile" select="name(//*[@* = 'C:/XML/currentAuthentifiedPackageDescriptor_N2.xml'])"/> This will search all of the nodes in the tree for one which has a attribute with the value specified and returns the name of that node. I am assuming that the file name is complete, in which case the starts-with function is not required. Steve -----Original Message----- From: Stephane.Le-Deaut@xxxxxxxxxx [mailto:Stephane.Le-Deaut@xxxxxxxxxx] Sent: Monday, August 20, 2001 11:41 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] get the name of a node which I know the value I have this xml file : <?xml version="1.0" encoding="ISO-8859-1"?> <XslParameter> <InputFile currentAuthentifiedPackageDescriptor1="C:/XML/currentAuthentifiedPackageDesc riptor_N1.xml" currentAuthentifiedPackageDescriptor2="C:/XML/currentAuthentifiedPackageDesc riptor_N2.xml" referenceAuthentifiedPackageDescriptor_Nectar="C:/XML/referenceAuthentifiedP ackageDescriptor_Nectar.xml" automate="C:/XML/automate.xml" user="C:/XML/user_prg_dha.xml"/> <OutputFile subsetDescriptor="C:/XML/subsetDescriptor.xml" xslTrack="C:/XML/XslTrack_Test_makeSubsetDescriptor_01.xml" xslError="C:/XML/XslError_Test_makeSubsetDescriptor_01.xml"/> <Parameter signature="C:/XML/Signature.xml"/> </XslParameter> I know the value of the "currentAuthentifiedPackageDescriptor2" attribute and I would like to assign a variable with the name of the node. I tried to use name() function like this <xsl:variable name="CurrentFile" select="name()[starts-with(@*,'C:/XML/currentAuthentifiedPackageDescriptor_N 2.xml')]"/> but it does not work. Please help me. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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