Subject: Re: [xsl] Constructing X number of elements From: Goetz Bock <bock@xxxxxxxxxxx> Date: Tue, 21 Aug 2001 15:53:44 +0200 |
> How can I produce X number of elements in XSLT, where X is defined in an > attribute of an element in the source XML file? > [ ... ] > I suppose I can't do this with the for-each-construct. Please help, there > has to be a way for doing this! :) No, this is a picture book usecase for recursively calling a named template. Something like: <xsl:template name="printStars"> <!-- how many stars to print --> <xsl:param name="stars">0</xsl:param> <!-- how many start are printed already --> <xsl:param name="count">0</xsl:param> <xsl:when test="count < starts"> <img src="starg.gif" /> <xsl:call-template name="printStars"> <xsl:with-param namen="start"> <xsl:value-of select="$stars" /> </xsl:with-param> <xsl:with-param name="count"> <xsl:value-of select="$count + 1" /> </xsl:with-param> </xsl:call template> </xsl:when> </xsl:template> You use it someway like: <xsl:template match="movie"> <div> <xsl:call-template name="printStars"> <xsl:with-param name="start"> <xsl:value-of select="@rating" /> <xsl:with-param> </xsl:call-template> </div> </xsl:template> PLEASE NOTE: this is all written from memory, please use a xsl-t reverence to check the syntax (UNTESTED) BTW: would someone ponate me a US powerbook g4 keyboard??? this german one realy su***. -- Goetz Bock IT Consultant Dipl.-Inf. Univ.
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