Subject: [xsl] returning distinct results From: "Tim" <xsl@xxxxxxxxxxxxxx> Date: 30 Aug 2001 11:54:53 -0000 |
Hi, I have a list of branches some of which are in the same town. I would like to generate some html to display just the list of towns in a two column list. I have the columns working but I can't work out how to remove duplicate towns. I am trying to order by town name and see if the previous name matches the current but the //town[position()-1] returns an empty set. Any ideas would be great. Ta, Tim. Example XML: <branches> <branch> <name>A branch</name> <town>Aberdeen</town> </branch> <branch> <name>Another branch</name> <town>Aberdeen</town> </branch> <branch> <name>Yet Another branch</name> <town>Bournemouth</town> </branch> </branches> XSL: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format"> <xsl:template match="/"> <xsl:call-template name="alltowns"/> </xsl:template> <xsl:template name="alltowns"> <xsl:variable name="t-size" select="count(//town)"/> <xsl:variable name="half" select="ceiling($t-size div 2)"/> <table> <tr> <td> <ul> <xsl:for-each select="//town[position() <= $half]"> <xsl:if test="position() = 1 | //town [position()-1]/text() != ./text()"> <li><a><xsl:attribute name="href">locationDetails.jsp?town=<xsl:value-of select="."/></xsl:attribute><xsl:value-of select="."/></a></li> </xsl:if> </xsl:for-each> </ul> </td> <td> <ul> <xsl:for-each select="//town[position() > $half]"> <li><a><xsl:attribute name="href">locationDetails.jsp?town=<xsl:value-of select="."/></xsl:attribute><xsl:value-of select="."/></a></li> </xsl:for-each> </ul> </td> </tr> </table> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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