RE: [xsl] Returning a Tree

Subject: RE: [xsl] Returning a Tree
From: "Sullivan, Dan" <dsullivan@xxxxxxxxxxx>
Date: Tue, 4 Sep 2001 12:45:20 -0700
A variable without a select attribute contains a result tree fragment,
which in effect is a string. There is no way to assign the result of a
call-template with the select attribute... so in effect call-template
always returns a result tree fragment, never a nodeset. So there is no
standard way to do what you are trying to do. Many XSLT processors,
however, have extension functions that will convert a result tree
fragment into a nodeset.


-----Original Message-----
From: Darren Hayduk [mailto:dhayduk@xxxxxxxxxxxxxxx]
Sent: Tuesday, September 04, 2001 3:28 PM
To: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx'
Subject: [xsl] Returning a Tree

I'm trying to construct a template (call-template) that will return a
set, and I can't figure out how to do it.

I've had success calling a template with a node-set (a, below),
assigning a
node-set to a variable which can be used in the same context (b, below),
not returning a node-set (c, below).

A: <xsl:call-template name="a"> <xsl:with-param select="//nodes"
B: <xsl:variable name="v" select="//nodes"/>
C: <xsl:template name="c"> <xsl:value-of>... -or-
and then
<xsl:variable name="vc">
  <xsl:call-template name="c">	
<xsl:for-each select="$vc"> ...

Is this possible??


Darren Hayduk | Network Management
Nauticus Networks, Inc.
200 Crossing Blvd, Framingham, MA 01702
508-270-0500 x299

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