RE: [xsl] Child Nodes

<-prev [Thread] next->	<-prev [Date] next->
Month Index \| List Home

RE: [xsl] Child Nodes

Subject: RE: [xsl] Child Nodes
From: Richard Mitchell <Richard.Mitchell@xxxxxxxxxxxxx>
Date: Fri, 7 Sep 2001 09:01:40 +0100

David
> > A predicate like [1<=count(*)] will do that for you.
> or, simpler: *
> 
> 
> <xsl:when test="*">there are children</xsl:when>
> <xsl:otherwise>there are none</xsl:otherwise>
> 
Hmmm won't this test for comments and processing instructions?

Richard

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
RE: [xsl] Child Nodes, (continued) Michael Kay - Thu, 6 Sep 2001 15:56:34 +0100 Sullivan, Dan - Thu, 6 Sep 2001 07:03:23 -0700 Oleg Tkachenko - Thu, 06 Sep 2001 17:38:25 +0200 David Carlisle - Thu, 6 Sep 2001 17:18:53 +0100 Richard Mitchell - Fri, 7 Sep 2001 09:01:40 +0100 <= David Carlisle - Sat, 8 Sep 2001 18:45:04 +0100 Ben Robb - Fri, 7 Sep 2001 09:35:20 +0100

<- Previous	Index	Next ->
Re: [xsl] Child Nodes, David Carlisle	Thread	Re: [xsl] Child Nodes, David Carlisle
RE: [xsl] How to output attribute w, Dmitri Ilyin	Date	RE: [xsl] XSLT browser support, Bryan Tulloch
	Month