[xsl] Re: Re:XSL for element containing mixed content.

Subject: [xsl] Re: Re:XSL for element containing mixed content.
From: "Yang" <sfyang@xxxxxxxxxxxxx>
Date: Mon, 10 Sep 2001 17:23:12 +0800
Hi, Sandeep,

Following xslt is a workable solution,  hopefully the gurus in the list
could provide you better solution.

Please note I am using msxml 3 by using  < xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
I move the html and body element into the top template instead of in each
template.

Using node select , it can catch the correct element occuring sequence
inside of  each templates.
**  xslt  **
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
<html><body>
 <xsl:apply-templates/>
</body></html>
</xsl:template>

<xsl:template match="directory">
 <br/><xsl:apply-templates select="node()"/><br/>


</xsl:template>

<xsl:template match="subdirectory">
<font color="red">
 <br/><xsl:apply-templates select="node()"/><br/>

 </font>
</xsl:template>

<xsl:template match="file">
<font color="blue">
 <br/><xsl:value-of select="."/></font><br/>
</xsl:template>
</xsl:stylesheet>

Hope it can give some help.
Cheers!


Sun-Fu Yang

sfyang@xxxxxxxxxxxxx



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