Re: [xsl] outputing a non existant element.

Subject: Re: [xsl] outputing a non existant element.
From: Jörg Heinicke <joerg.heinicke@xxxxxx>
Date: Wed, 12 Sep 2001 21:08:08 +0200

what about this snippet:

    <xsl:when test="fruit">
        <xsl:value-of select="fruit"/>

Getting the value out of the schema-file is not possible I think.

I know something about a default-value of an attribute. If the attribute is
not specified the XSLT-processor returns this default-value. But I heard,
this behaviour is not specified too. It works in Xalan.


----- Original Message -----
From: "Auguste Oumar" <oumar_a@xxxxxxxx>
To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, September 12, 2001 7:17 PM
Subject: [xsl] outputing a non existant element.

> Hi,
> i have one optional element in my schema-file say:
> <fruit>orange</fruit>.The default value of fruit is
> "apple".I would like to have a xslt-transformation
> which gives me the content of the fruit element if it
> appears in the xml-file or its default value if it
> doesn't appear.I have problem giving out the default
> value when the element doesn't appear in the
> xml-file.How can i solve it ?
> Thanks for help.
> Auguste

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