RE: [xsl] How do you get the non-transformed character entity out of MSXML3.0

["Julian Reschke" <julian.reschke@xxxxxx>]

Why would you want that?

In XML, "less-than" is serialized as "<".

When accessing the DOM, you get the "raw" character ("<").

Serializing the DOM again (using save() or the xml property) will turn it
back into "&lt;".

I fail to see a problem here.


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of
> jdgarrett@xxxxxxxxxx
> Sent: Sunday, September 16, 2001 12:37 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] How do you get the non-transformed character entity out
> of MSXML3.0
>
>
>
>
> Here is the node
>
> <Customer  number="125487"   NumberOfPurchases="&lt;4" >Joe &amp; Bill's
> Shop</Customer>
>
> (I am just loading up an xml document via
> Visual Basic inside of a code module and then accessing
> the xml via manipulation of the DOM via Visual Basic, I am
> not transforming the xml with an xslt file...that
> would happen later and that is why the element and attribute
> values in the Customer node must stay in their untransformed state)
>
> What I am trying to retrieve from the node attribute
> NumberOfPurchases (using MSXML 3.0 ) is :
>
> &lt;4
>
>
> What I have been able to get via one of the properties in
> MSXML3.0
>
> accessing the xml property on the node attribute you get
> NumberOfPurchases="&lt;4"
>
> accessing the text property on the node attribute you get
> <4
>
> Anyone know how to return just  &lt;4 using one of the
> property's or methods of MSXML3.0
>
> Thanks
> Jim Garrett
>
>
>
>
>
>
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