RE: [xsl] questions?

Subject: RE: [xsl] questions?
From: "Mihir D. Gore" <mihirg@xxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 18 Sep 2001 10:50:07 +0530
Sorry i actually mis-framed my question slightly. I know that xsl creates a
new output file and does not modify the existing file.

Mihir D. Gore
Geometric Software Solutions Limited
Pune Infotech Park
Tel: 95213930404

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-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Christopher
R. Maden
Sent: Tuesday, September 18, 2001 10:28 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] questions?

At 21:29 17-09-2001, Mihir D. Gore wrote:
>If i have a operation like "insert node n as the i th  child of node p" ,
>what will be the the xsl?

To repeat a FGA[*], XSLT can't change the source.  It reads the source and
writes output.

>for example
>         <author>P.G.Wodehouse</author>
>         <name>Good Morning Jeeves</name>
>         <price>20</price>
>if i  add the node <review></review> as the 3rd child of book then the xsl
>will be
>         <author>P.G.Wodehouse</author>
>         <name>Good Morning Jeeves</name>
>         <review>Some comments here</review>
>         <price>20</price>

What you want to do is copy the book, with the review added.  You could do
this by starting with the identity transform (see the XSLT Recommendation)
and adding

<xsl:template match="book">
   <xsl:copy select=".">
     <xsl:apply-templates select="*[position() &lt; 3]"/>
     <review>Some comments here</review>
     <xsl:apply-templates select="*[position() >= 3]"/>


[*] Frequently given answer.
Christopher R. Maden, Principal Consultant, HMM Consulting Int'l, Inc.
DTDs/schemas - conversion - ebooks - publishing - Web - B2B - training
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