Re: [xsl] Re: xsl:element

Subject: Re: [xsl] Re: xsl:element
From: Mike Brown <mike@xxxxxxxx>
Date: Sun, 23 Sep 2001 04:15:51 -0600 (MDT)
> > So if you did something like 
> > 
> > <xsl:element name="foo" xmlns="blah">
> >   <bar/>
> > </xsl:element>
> > 
> > then you should get
> > 
> > <foo>
> >   <bar xmlns="blah"/>
> > </foo>

I made this statement by reading the spec, not by actually trying it out :)

> Using MSXML3 you get:
> 
> <foo xmlns="blah"><bar /></foo>
>
> [...]
> With Saxon the results are, respectively:
> 
> <foo xmlns="blah"><bar/></foo>

I am at a loss to explain this. Perhaps I am misreading the spec.
Michael?

> If you use the "namespace" attribute on an xsl:element like this:
>      <xsl:element name="foo" namespace="blah">
>        <bar/>
>      </xsl:element>
> 
> Then you get:
> 
> <foo xmlns="blah"><bar xmlns="" /></foo>
>
> [with Saxon...]
> <foo xmlns="blah"><bar/></foo>

Here MSXML looks more correct than Saxon.

The literal result element doesn't have any namespace nodes on it,
so it has no namespace bindings in effect; it can only be in the
default/null namespace. The namespace of the containing element
shouldn't matter. Or should it?

Argh.

   - Mike
____________________________________________________________________________
  mike j. brown, fourthought.com  |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  personal: http://hyperreal.org/~mike/

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