Subject: [xsl] Position X Sort-> Please urgent! From: "Paulo Henrique S. Bermejo" <bermejo@xxxxxxxxxxx> Date: Thu, 27 Sep 2001 15:20:47 -0300 |
Hi all, I'm with problems with my transformation and I need to give my project in next week, and need to make others things. Well... I've 2 xml documents and 1 xsl document. The first doc xml (XMLORIGINAL.XML) The second xml document (XMLADD.XML) have informations about first document. The relashion this elements is for position, but I need to print this context using the sort, and I'm having problems with this. Exists a formal of to get a position of element in original formate? My example: <!-- XMLORIGINAL.XML --> <?xml-stylesheet type="text/xsl" href="XSLORIGINAL.XSL"?> <ORIGINAL> <TEST>1</TEST> <TEST>2</TEST> <TEST>3</TEST> <TEST>4</TEST> <TEST>5</TEST> </ORIGINAL> <!-- XMLADD.XML --> <ADDS> <ADD>A</ADD> <!-- This element if referent the 1º <TEST> element --> <ADD>B</ADD> <!-- This element if referent the 2º <TEST> element --> <ADD>C</ADD> <!-- This element if referent the 3º <TEST> element --> <ADD>D</ADD> <!-- This element if referent the 4º <TEST> element --> <ADD>E</ADD> <!-- This element if referent the 5º <TEST> element --> </ADDS> <!-- XSLORIGINAL.XSL --> <xsl:template match="ORIGINAL"> <xsl:for-each select="TEST"> <xsl:sort select="." data-type="number" order="descending"/> <xsl:value-of select="."/> <xsl:variable name="var_pos" select="position()"/> <xsl:value-of select="document('XMLADD.XML')/ADDS/ADD[$var_pos]"> </xsl:for-each> </xsl:template> I need to print so: ------------------ 5E 4D 3C 2B 1A And my result is: ------------------ 5A 4B 3C 2D 1E If I can't to print so, then exist another form???? Thanks all, Paulo. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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