Re: FW: [xsl] xpath expression needed

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

At 03:25 PM 10/2/01, you wrote:
> I want to match all nodes whose following-sibling::level1 has the same value
> for @type.  So in this case, only the first 'level1' node would be matched.
>
> How about:
>
> level1[@type = following-sibling::level1/@type]
>
> Would that work?

Yes, except for the small but very important detail that this will give you 
every level1 that have *any* following-sibling::level1 with a matching @type.

To check just the directly following sibling level1, amend to:

level1[@type = following-sibling::level1[1]/@type]

The rule for node-set equality is in the XPath spec, 3.4. That's what you 
have inside the predicate (comparing the node-set consisting of @type to 
the node-set consisting of following-sibling::level1/@type).

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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