[xsl] Re: xsl not working when transforming a schema

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

> I'm using xsl on the schema below to extract the attribute "name",  from
> the element "element".
> 
> Schema
> <?xml version="1.0" encoding="UTF-8"?>
>   <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema";
> elementFormDefault="qualified">
>     <xsd:element name="Marc"/>
>     <xsd:element ref="5"/>
> </xsd:schema>
> 
> 
> XSL
> <?xml version='1.0'?>
> <xsl:stylesheet version="1.0"
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>  xmlns:xsd="http://www.w3.org/2000/10/XMLSchema";>

[skipped the rest]

With this namespace defined in your stylesheet, xsd:someName will look for names in
the namespace "http://www.w3.org/2000/10/XMLSchema";

On the other side, xsd:anyName in your xml belong to completely different namespace:
"http://www.w3.org/2001/XMLSchema";

Therefore, you're looking for names that are not there.

What is important is the namespace-uri -- not the local name!

Hope this helped.

Cheers,
Dimitre Novatchev.

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