Subject: [xsl] Re: strange behaviour in Xalan From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Sat, 20 Oct 2001 07:12:52 -0700 (PDT) |
> <xsl:template match="boxes"> > <xsl:copy-of select="*|@*"/> > </xsl:template> > > , which in my eyes can cause problems, if the root-element has attributes. > So I tested it with Xalan 2.2.D11. But I get a really strange output: > > XML > > <?xml version="1.0" encoding="UTF-8"?> > <boxes test="1"> > <box id="1234"> > <title>Ciao</title> > <body>This is the body of the box</body> > </box> > </boxes> > > XSL > > <?xml version="1.0"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; > version="1.0"> > <xsl:output indent="yes"/> > <xsl:template match="boxes"> > <xsl:copy-of select="*|@*"/> > </xsl:template> > </xsl:stylesheet> > > Output > > <?xml version="1.0" encoding="UTF-8"?> > <box xmlns:xml="http://www.w3.org/XML/1998/namespace"; test="1" id="1234"> > <title>Ciao</title> > <body>This is the body of the box</body> > </box> > > 1. Why is the attribute test="1" not causing an error, but will be copied to > the new root-element? Because your XSLT processor is buggy. An attribute node will be copied into the current output destination only in case there is a still open element (copied) there. This is exactly the same as for xsl:attribute or xsl:copy. In this specific case an XSLT processor must either signal the error (Saxon) or ignore it silently (MSXML3). Copying an attribute to another element node is a bug. > 2. Where does ' xmlns:xml="http://www.w3.org/XML/1998/namespace"; ' come > from? Every element node in a well-formed xml document has the "xml" namespace node. However, it is "default" and need not be explicitly declared. Outputting it as a namespace declaration may be considered as a bugette. Cheers, Dimitre Novatchev. __________________________________________________ Do You Yahoo!? Make a great connection at Yahoo! Personals. http://personals.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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