Subject: Re: [xsl] reordering output (Again) From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Mon, 22 Oct 2001 14:34:03 +0100 |
Goetz Block wrote: > On Mon, Oct 22 '01 at 14:42, Eric Smith wrote: >> In short, perhaps someone may advise: >> Is reordering of nodes in the output possible? > Yes. > > But could you be more elaborated on what and how you want to > reorder. If you have a specific criteria, you can use <xsl:for-each > sort=''>, but it might be more complicated than this. Goetz meant: <xsl:for-each select="..."> <xsl:sort select="..." /> ... </xsl:for-each> You can also use xsl:sort within xsl:apply-templates to change the order in which nodes are processed with templates. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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