Subject: RE: [xsl] How to include the name of a xml document in the content of a tag. From: "Chris Bayes" <chris@xxxxxxxxxxx> Date: Tue, 23 Oct 2001 19:39:23 +0100 |
Beatriz, Depending on how you are doing the transform the easiest way to do it is to pass the filename in as a parameter to the transform. Then add <xsl:param name="filename" select="noFileNamePassedToStylesheet" /> To your stylesheet Ciao Chris XML/XSL Portal http://www.bayes.co.uk/xml > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Rua Costas, Beatriz > Sent: 23 October 2001 17:50 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] How to include the name of a xml document in > the content of a tag. > > > Hello everyone, > I am using a xsl document to do several transformations in xml files. > I would like to include in the xml document the name of the > file like the content of a tag. > > E.g.: > > Original XML (before XSL Transformation): > > <?xml version="1.0" encoding="ISO8859-1" ?> > <CATALOG> > <CD> > <TITLE>Empire Burlesque</TITLE> > <ARTIST>Bob Dylan</ARTIST> > <COUNTRY>USA</COUNTRY> > <COMPANY>Columbia</COMPANY> > <PRICE>10.90</PRICE> > <YEAR>1985</YEAR> > </CD> > . > . > . > > Final XML (after XSL Transformation): > > <?xml version="1.0" encoding="ISO8859-1" ?> > <CATALOG> > <CD> > <DOC>The_name_of_the_xml_document</DOC> > <TITLE>Empire Burlesque</TITLE> > <ARTIST>Bob Dylan</ARTIST> > <COUNTRY>USA</COUNTRY> > <COMPANY>Columbia</COMPANY> > <PRICE>10.90</PRICE> > <YEAR>1985</YEAR> > </CD> > . > . > . > > Is there any easy way to get the name of the xml document > using a xsl file? > > Thank you. > > Beatriz > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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