Subject: Re: [xsl] Sorting and grouping From: ronald heller <ronald@xxxxxxxxxxx> Date: Tue, 30 Oct 2001 11:40:58 +0100 |
XML: <list> <item at="d">d</item> <item at="e">e</item> <item at="i">i</item> <item at="k">k</item> <item at="l">l</item> <item at="a">a</item> <item at="b">b</item> <item at="c">c</item> <item at="j">j</item> <item at="f">f</item> <item at="g">g</item> <item at="h">h</item> <item at="a">a</item> <item at="b">b</item> <item at="c">c</item> </list>
xSLT: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="Windows-1252" />
<xsl:template match="list"> <xsl:apply-templates select="item"> <xsl:sort select="@at" order="ascending"/> </xsl:apply-templates> </xsl:template>
</xsl:template> </xsl:stylesheet>
RH At 10:33 AM 10/30/01 +0100, you wrote:
Hi, can someone help me with the following problem?
I have an unordered list of items: <list> <item at="..."> ... </item> ... <item at="..."> ... </item> </list>
I want to sort this list by an 'at' attribute and then display these sorted items in groups. Each group should consist of a fixed number (let's say 5) of items. I can solve this problem only by first sorting the list into a temporary .xml file and then use this file for grouping. What's even worse, I'am not able to handle the problem in one single xsl transformation file.
To be more specific, one can't do it in one pass like this: <xsl:apply-templates select="item"> <xsl:sort select="@at" order="descending"/> </xsl:apply-templates> .... <xsl:template match="item[(position() mod 5) = 1]"> <xsl:variable name="group" select=".|following::item[position() < 5]"/> because last 'select' selects following items in document order (not in sorted order).
Is there a way to solve that without creating a temporary file?
Thank you for your help. Zdenek
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