Re: [xsl] Link Generation using keys

Subject: Re: [xsl] Link Generation using keys
From: David Carlisle <davidc@xxxxxxxxx>
Date: Mon, 12 Nov 2001 14:01:54 GMT
> <xsl:template name="x">
>  <xsl:param name="id" select="1" />
>  <xsl:for-each select="key('ids', $id)">
>  <xsl:element name="a">
>   <xsl:attribute name="href"><xsl:value-of select="id"/></xsl:attribute>
>   <xsl:text><xsl:value-of select="title"/></xsl:text>
>  </xsl:element>
> ...
> </xsl:template>

That's corrrect, although just a long form of

<xsl:template name="x">
 <xsl:param name="id" select="1" />
 <xsl:for-each select="key('ids', $id)">
 <a href="{id}">
 <xsl:value-of select="title"/>

> This does not work - there are no links generated; what would be the
> proper way  to access the values ? 

The idea is that you give the people on the list some hint as to what's

Do you mean you get no <a> element? In this case presumably key()
returned an empty node set. Unless you show your xsl:key definition and
a sample input there's not a lot that can be said about that.

Or do you mean that you got an <a> but an empty href attribute and content
In that case the nodes returned by the key probably haven't got id and
title sub elements.

or do you mean you don't get anything, even the ... in which case
presumably the whole template is never called.


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