Re: [xsl] XSL Grouping

["David B. Bitton" <david@xxxxxxxxxxxxxx>]

I have implemented this:

			<xsl:for-each select="Transaction[count(. | key('TransactionsByStatus', Status)[1]) =
1]">
				<xsl:sort select="Status"/>
				<tr class="Report">
					<td colspan="8">
						<b>
						<xsl:choose>
							<xsl:when test="Status='C'">
								<xsl:value-of
select="count(key('TransactionsByStatus', Status))"/><xsl:text> confirmed transaction</xsl:text>
							</xsl:when>
							<xsl:when test="Status='A'">
								<xsl:value-of
select="count(key('TransactionsByStatus', Status))"/><xsl:text> accepted, awaiting confirmation</xsl:text>
							</xsl:when>
							<xsl:when test="Status='R'">
								<xsl:value-of
select="count(key('TransactionsByStatus', Status))"/><xsl:text> rejected</xsl:text>
							</xsl:when>
							<xsl:when test="Status='Y' or Status = 'N'">
								<xsl:value-of
select="count(key('TransactionsByStatus', Status))"/><xsl:text> transaction awaiting submission</xsl:text> 
							</xsl:when>			
							<xsl:when test="Status='2' or Status='3' or Status='4'
or Status='5' or Status='6' or Status='7' or Status='8' or Status='9'">
								<xsl:value-of
select="count(key('TransactionsByStatus', Status))"/><xsl:text> transaction awaiting </xsl:text> <xsl:value-of
select="Status" /><xsl:text> more approvals</xsl:text>
							</xsl:when>
						</xsl:choose>
						</b>
					</td>
				</tr>
				<xsl:for-each select="key('TransactionsByStatus', Status)">
					<xsl:sort select="*[local-name() = string($sortby)]"
data-type="{$datatype}" order="{$order}"/>
					
					<xsl:for-each select="key('TransactionsByStatus', Status)

[generate-id() =

generate-id(key('TransactionsByStatusAndCurrencyCode',

concat(Status, '::', CurrencyCode))[1])]">
												
							<tr><td class="ReportD" colspan="8"><xsl:value-of
select="CurrencyCode"/></td></tr>
							
							<xsl:for-each
select="key('TransactionsByStatusAndCurrencyCode',

concat(Status, '::', CurrencyCode))">


and I'm getting all transaction repeated for all currencycode, so if there are three transactions in the group, I
get three under each unique currencycode, hrm. :)

On Mon, Nov 12, 2001 at 05:56:22PM +0000, Jeni Tennison wrote:
> Hi David,
> 
> > This is one transaction. First we group by Status, no prob. Now I
> > want to group by CurrencyCode within each Status group. I'm just not
> > seeming to get the right combo of xsl:key and key() XPath in the sub
> > for-each. Can someone lend a hand? Tx :)
> 
> Sure. The key that you use for the second level group has to index
> each Transaction by a combination of its Status and its CurrencyCode.
> The easiest way to get such a combination value is using the concat()
> function, so try:
> 
> <xsl:key name="TransactionsByStatusAndCurrencyCode"
>          match="Transaction"
>          use="concat(Status, '::', CurrencyCode)" />
> 
> [Obviously you don't have to use such a long name, I'm just doing so
> to make things clear.]
> 
> At the point where currently you're retrieving all the Transaction
> elements with a particular status, you need to filter that set to
> include only those that have that Status *and* have a unique
> CurrencyCode, with something like:
> 
>   key('TransactionsByStatus', $status)
>     [generate-id() =
>      generate-id(key('TransactionsByStatusAndCurrencyCode',
>                      concat($status, '::', CurrencyCode))[1])]
> 
> And once you're processing such a Transaction, you can get all the
> other Transaction elements with the same Status and CurrencyCode with:
> 
>   key('TransactionsByStatusAndCurrencyCode'
>       concat(Status, '::', CurrencyCode))
> 
> I hope that helps,
> 
> Jeni
> 
> ---
> Jeni Tennison
> http://www.jenitennison.com/
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

-- 

David B. Bitton
david@xxxxxxxxxxxxxx

Diversa ab illis virtute valemus.

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