Subject: Re: [xsl] Getting several instances to be parsed in one variable From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 13 Nov 2001 11:56:21 GMT |
> so I don't want to use any extension to convert one to the > other. well if you don't you are stuck. > I thought I could use xsl:apply-templates or xsl:for-each, no that's the whole point: a result tree fragment only has the same operations that you can do on a string. You can't apply templates or for-each or extract child nodes with /. More or less every XSLT engine has a node-set() function, and it is likely to be implicit in later releases of XSLT so this is probably the most portable of all extensions. If your file had had the full names including the ".xml" then you could have gone <xsl:variable name="g_modules" select="document(/root/my/filenames, document(concat($p_my_dir, '/', /root/my/filenames[1])))"/> where the first call to document() produces a node set of all the documents accessed by relative URI in the filenames elements, taking a base URI from the first of them. This would put the root nodes of all the documents into your variable but If the xml file has the file names without ".xml", I don't think you can add the ".xml" and still use the feature of teh document() function to iterate over a node set. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Getting several instances to , Paul Terray | Thread | RE: [xsl] Getting several instances, Michael Kay |
RE: [xsl] Positions, TSchutzerWeissmann | Date | [xsl] forming a link w/ arguments?, Michael |
Month |