RE: [xsl] nodes order in union

Subject: RE: [xsl] nodes order in union
From: "Oleg Tkachenko" <olegt@xxxxxxxxxxxxx>
Date: Sat, 17 Nov 2001 20:14:08 +0200
Hello philippe!

>     <xsl:template match="child::node() | attribute::*" mode="copie">
> 		<xsl:copy>
> 			<xsl:apply-templates select="@*|node()" 
> mode="copie"/>
> 		</xsl:copy>
>     </xsl:template>
> no error happens, and the copy is quite correct.
> Is the XSLT processor (Saxon, actually) cleaver enougth to process the
> nodes in right order ? Or is there somewhere in Xpath or XSLT a rule
> which says that in this particulary case, union must yield a node-set
> where attributes are located before other nodes (I can't find it)? 

It's clear Saxon is very clever, but fortunately to others, "cleaver" processors :) there is distinct spec definition for this case.
<xsl:apply-templates> processes nodes in document order, see and according to that order "The attribute nodes and namespace nodes of an element occur before the children of the element.".

Oleg Tkachenko,
Multiconn International, Israel 

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