RE: [xsl] nodes order in union

["Oleg Tkachenko" <olegt@xxxxxxxxxxxxx>]

Hello philippe!

>     <xsl:template match="child::node() | attribute::*" mode="copie">
> 		<xsl:copy>
> 			<xsl:apply-templates select="@*|node()" 
> mode="copie"/>
> 		</xsl:copy>
> 		
>     </xsl:template>
>     
> no error happens, and the copy is quite correct.
> 
> Is the XSLT processor (Saxon, actually) cleaver enougth to process the
> nodes in right order ? Or is there somewhere in Xpath or XSLT a rule
> which says that in this particulary case, union must yield a node-set
> where attributes are located before other nodes (I can't find it)? 

It's clear Saxon is very clever, but fortunately to others, "cleaver" processors :) there is distinct spec definition for this case.
<xsl:apply-templates> processes nodes in document order, see http://www.w3.org/TR/xpath#dt-document-order and according to that order "The attribute nodes and namespace nodes of an element occur before the children of the element.".

---
Oleg Tkachenko,
Multiconn International, Israel 


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