RE: [xsl] Converting attributes to elements and preserving the hierarchy

["Samuel Abraham" <samuel.abraham@xxxxxx>]

hi,
Thanks.It worked.I started with XSLT just  2 days back.
So excuse me if some obvious links or documents clearly states the answer to the question below.

How do I decide  when to use <xsl:for-each> or a template ?
  regds
  Samuel Abraham



---------------------------------------- Message History ----------------------------------------


From: chris@xxxxxxxxxxx@lists.mulberrytech.com on 12/19/2001 08:44 AM GMT

Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx

DELEGATED - Sent by:     owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx


To:   xsl-list@xxxxxxxxxxxxxxxxxxxxxx
cc:
Subject:  RE: [xsl] Converting attributes to elements and preserving the hierarchy


Beginners rule #1 Never use for-each. By using for-each here you are
flattening you data. Use a template instead

     <xsl:template match="nfield">
          <xsl:element name="{@fldname}">
                <xsl:apply-templates />
             <xsl:value-of select="@reserve2"/>
           </xsl:element>
     </xsl:template>

Ciao Chris


XML/XSL Portal
http://www.bayes.co.uk/xml


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of
> Samuel Abraham
> Sent: 19 December 2001 07:56
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Converting attributes to elements and
> preserving the hierarchy
>
>
> Hi all,
> I am trying to transform an xml document into a resultant xml
> where the attributes of the source are converted to elements
> and one of the attributes as the value of the node.(Using
> Xalan ). eg for source XML
> :
>       <nfield fldname="DETAILS" >
>       <nfield fldname="Creation_Date"  reserve2="20122001"/>
>       <nfield fldname="REPEATER_OUTER">
>         <nfield fldname="Address1"reserve2="SHENTON WAY"/>
>           <nfield fldname="REPEATER" length="0" fldtype="F">
>                <nfield fldname="Rate" reserve2="25"/>
>      </nfield>
>         </nfield>
>       </nfield>
> I am able to do the transformation but the result doent have
> the child parent realtionship.
>
> I used the template
>   <xsl:template match="/">
>     <xsl:element name="{/template/header/tmplname}">
>       <xsl:for-each select="/template/format//nfield">
>            <xsl:element name="{@fldname}">
>              <xsl:value-of select="@reserve2"/>
>            </xsl:element>
>       </xsl:for-each>
>     </xsl:element>
>   </xsl:template>
>
> The result was something like this
> <DETAILS/>
> <Creation_Date>20122001</Creation_Date>
> <REPEATER_OUTER/>
>  <Address1>SHENTON WAY</Address1>
> <REPEATER/>
> <RATE>25</RATE>
>
> Actually I need to get
>   <DETAILS>
>      <Creation_Date>20122001</Creation_Date>
>      <REPEATER_OUTER>
>           <Address1>SHENTON WAY</Address1>
>           <REPEATER>
>                <RATE>25</RATE>
>           </REPEATER>
>      </REPEATER_OUTER>
>  </DETAILS>
>
> Where am I going wrong?Can someone please point out the
> problem..... thanks  Samuel Abraham
>
>
>
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