[xsl] re: general problem

[saodl@xxxxxxxx]

i'm no javascript expert, but i'm using a piece of
code like this to grab the current xml document for
manipulation in a javascript function.  

var xmlDoc = document.XMLDocument;
if (xmlDoc == null){
  xmlDoc = navigator.XMLDocument;
}

hope that helps.

siri

------andrew@xxxxxxxxxxxxxxxxxxxxxxx wrote------

Hi all,

Imagine I have a set of nodes like this:

<root>
<a>
  <b>
  <c>
  <d>
  <e>
</a>
<a>
  <b>
  <c>
  <d>
  <e>
</a>
</root>

I apply a stylesheet to the xml to output a table that
displays certain
elements of each <a> such as:

<tr>
  <td>b , c, d</td>
</tr>

Say I want to include a button next to that row that,
when clicked, opens a
window displaying -all- the elements for that <a>.

I can do this by calling a javascript function, passing
the position of the
<a> node as a parameter, and using the DOM to extract
the information I
want.  However, this currently relies on me hard-coding
the name of the xml
file (xmlObj.load('xmlfile')) into the function, which
then makes the
stylesheet useless for all but one xmlfile.

If you understand what Im asking ;) is there a better
way of doing this?

Thanks to anyone on my wavelength, apolgies to everyone
else

cheers

andrew

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