Subject: [xsl] Parameter Type problem From: "Fort, Karen" <Karen.Fort@xxxxxxxxxxxxxx> Date: Fri, 25 Jan 2002 18:48:40 +0100 |
Hi, I have a problem trying to retrieve the value of one node in the schema to affect it to a parameter in the data... In fact, the 'concat' function transforms it into a string and then I cannot turn it into the right node type... It's a bit difficult to explain for me, so, here's the code: <xsl:template match="z:row"> <xsl:variable name="tmplg" select="concat('@',/xml/s:Schema/s:ElementType/s:AttributeType[@rs:name='term1.language_']/@name)"></xsl:variable> <xsl:apply-templates select="@*"> <xsl:with-param name="language1" select="$tmplg"></xsl:with-param> </xsl:apply-templates> </xsl:template> <xsl:template match="@*"> <xsl:param name="language1"></xsl:param> <xsl:choose> <xsl:when test="contains(/xml/s:Schema/s:ElementType/s:AttributeType[@name = name(current())]/@rs:name,'term1.baseform_')"> <xsl:call-template name="xts-language-mapping"> <xsl:with-param name="language" select="$language1" /> </xsl:call-template> </xsl:when> The problem is the parameter is then of string type and not node... How can I "cast" it to a node? I'm sure it's very simple, but I cannot find my way through this! Thanks! Karen XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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