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Subject: Re: [xsl] Meunchian Method - Grouping with attributes  From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Sat, 26 Jan 2002 10:17:59 -0500  | 
I'm having a tough time grouping on an attribute where I need to get only unique values of the domain attribute for each unique technology.
t:\ftemp>type brian.xml
<?xml version="1.0" encoding="utf-8"?>
<document>
  <products>
    <product>Product1
      <technology domain="xyz">tech1</technology>
      <technology domain="abc">tech1</technology>
      <technology domain="xyz">tech2</technology>
      <technology domain="xxx">tech2</technology>
      <technology domain="xyz">tech3</technology>
    </product>
    <product>Product2
      <technology domain="xyz">tech1</technology>
      <technology domain="abc">tech1</technology>
      <technology domain="zzz">tech2</technology>
      <technology domain="xxx">tech2</technology>
      <technology domain="aaa">tech3</technology>
    </product>
  </products>
</document>t:\ftemp>type brian.xsl <?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
  <xsl:variable name="technologies" select="//technology"/>
  <xsl:for-each select="$technologies">
    <xsl:if test="generate-id(.)=
                  generate-id($technologies[.=current()])">
      <xsl:value-of select="."/><xsl:text>
</xsl:text>
      <xsl:variable name="domains"
                    select="$technologies[.=current()]/@domain"/>
      <xsl:for-each select="$domains">
        <xsl:if test="generate-id(.)=
                      generate-id($domains[.=current()])">
          <xsl:text>     domain = </xsl:text>
          <xsl:value-of select="."/><xsl:text>
</xsl:text>
        </xsl:if>
      </xsl:for-each>
    </xsl:if>
  </xsl:for-each>
</xsl:template>t:\ftemp>xt brian.xml brian.xsl
tech1
     domain = xyz
     domain = abc
tech2
     domain = xyz
     domain = xxx
     domain = zzz
tech3
     domain = xyz
     domain = aaa
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