[xsl] sort

[Frederic Leclercq <frederic@xxxxxxxxxxxxx>]

Hi,

I have following XML :

<root>
	<persistentId>4317922674763656975</persistentId>
     <hyperlink>hyperlink</hyperlink>
     <description>beschrijving</description>
     <language>Nederlands</language>
     <keywords>sleutel</keywords>
     <fileName>kamerWebsite.doc</fileName>
     <internalUse>false</internalUse>
     <hits>0</hits>
     <subroot>
       <persistentId>2</persistentId>
       <state>send</state>
     </subroot>
     <person>
       <persistentId>1</persistentId>
       <firstName> Administrator</firstName>
       <lastName> </lastName>
       <supelogin>
         <login>administrator</login>
         <user>true</user>
         <coordinator>false</coordinator>
         <supervisor>false</supervisor>
         <administrator>true</administrator>
       </supelogin>
     </person>
     <storageType>FILE FILE</storageType>
     <visibleEverywhere>false</visibleEverywhere> 
</root>

that's one "record" - i have 100's of them in the XML string.

Following works perfect if i would like to sort on one of the first level tags...
<xsl:apply-templates>
		<xsl:sort select="*[name()=$sortering]" order="{$direction}"/>
</xsl:apply-templates>

But now i would like to sort the xmlstring on "root.person.supelogin.login"
Anybody could help me out ?

Thx,
Fred.





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