Subject: Re: [xsl] Parsing mixed content nodes From: "Joerg Heinicke" <joerg.heinicke@xxxxxx> Date: Fri, 8 Feb 2002 22:45:21 +0100 |
the general processing: <!-- every node, that must not be handled especially, e.g. <item>, <p> --> <!-- this template is not needed, it's similar to built-in templates --> <xsl:template match="*"> <xsl:apply-templates/> </xsl:template> <!-- <a> needs to be handled in another way --> <xsl:template match="a"> <xsl:apply-templates/> <xsl:text> (</xsl:text> <xsl:value-of select="@href"/> <xsl:text>) </xsl:text> </xsl:template> <!-- <br> too --> <xsl:template match="br"> <xsl:text> </xsl:text> </xsl:template> For every node which must be handled, write a own template. For example the <p>-node, if you need linebreaks: <xsl:template match="p"> <xsl:apply-templates/> <xsl:text> </xsl:text> </xsl:template> Regards, Joerg ----- Original Message ----- From: "Jason Macki" <jmacki@xxxxxxx> > Hello, > > I'm writing a stylesheet that converts some HTML code into text. > > For example, this xml: > > <item> > <p> > This is a <a href="link.htm">link</a><br />This is a new > line. > </p> > <item> > > would be translated into this text: > > This is a link(link.htm) > This is a new line. > > I can use the descendant axis to retrieve the "p" node, the "a" node, > and the "br" node from the "item" element. > > My problem is combining them back together, in the correct order. > > I'd like to be able to write XSLT that would output: > > "this is a", then the "a" node, then a line break for the "br" node, and > then output the remaining text. > > Does anyone have any ideas? > > Thanks very much, > Jason XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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