Re: [xsl] Parsing mixed content nodes

["Joerg Heinicke" <joerg.heinicke@xxxxxx>]

the general processing:

<!-- every node, that must not be handled especially, e.g. <item>, <p> -->
<!-- this template is not needed, it's similar to built-in templates -->
<xsl:template match="*">
    <xsl:apply-templates/>
</xsl:template>

<!-- <a> needs to be handled in another way -->
<xsl:template match="a">
    <xsl:apply-templates/>
    <xsl:text> (</xsl:text>
    <xsl:value-of select="@href"/>
    <xsl:text>) </xsl:text>
</xsl:template>

<!-- <br> too -->
<xsl:template match="br">
    <xsl:text>&#10;</xsl:text>
</xsl:template>

For every node which must be handled, write a own template. For example the
<p>-node, if you need linebreaks:

<xsl:template match="p">
    <xsl:apply-templates/>
    <xsl:text>&#10;</xsl:text>
</xsl:template>

Regards,

Joerg

----- Original Message -----
From: "Jason Macki" <jmacki@xxxxxxx>


> Hello,
>
> I'm writing a stylesheet that converts some HTML code into text.
>
> For example, this xml:
>
> <item>
> <p>
>     This is a <a href="link.htm">link</a><br />This is a new
> line.
> </p>
> <item>
>
> would be translated into this text:
>
> This is a link(link.htm)
> This is a new line.
>
> I can use the descendant axis to retrieve the "p" node, the "a" node,
> and the "br" node from the "item" element.
>
> My problem is combining them back together, in the correct order.
>
> I'd like to be able to write XSLT that would output:
>
> "this is a", then the "a" node, then a line break for the "br" node, and
> then output the remaining text.
>
> Does anyone have any ideas?
>
> Thanks very much,
> Jason


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