Subject: RE: [xsl] determining position of a document included using document function From: "Bryan Rasmussen" <bry@xxxxxxxxxx> Date: Thu, 14 Feb 2002 11:48:43 +0100 |
Thanks Gennady, that's useful. >For example, using the following XML file ><?xml version="1.0" ?> ><files> > <file href="data1.xml" /> > <file href="data2.xml" /> > <file href="data3.xml" /> ></files> >I declare a variable, which is a union of the documents ><xsl:variable name="merged" select="document(/files/file/@href)" /> >Then I store generated id for each document root in another variable: ><xsl:variable name="tops"> > <xsl:for-each select="/files/file"> > <file> > <xsl:copy-of select="@href" /> > <xsl:attribute name="id"><xsl:value-of >select="generate-id(document(@href))" /></xsl:attribute> > </file> > </xsl:for-each> ></xsl:variable> >When I need to know the file URL, I do the following: ><xsl:template match="myElement"> >... > <xsl:variable name="currentTop" select="generate-id(/)" /> > <url> > <xsl:value-of select="msxsl:node-set($tops)/file[@id = $currentTop]/@href" >/> > </url> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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