Subject: [xsl] xsl:attribute (was Re: URL query as table data) From: Antonio Bueno <atnbueno@xxxxxxxxxx> Date: Sun, 17 Feb 2002 18:10:48 +0100 |
Hello, everybody. WARNING: XSLT newbie here. Mike answered to Harry: MB> Never mind. This is what you're trying to do: MB> <A> MB> <xsl:attribute name="HREF"> MB> <xsl:text>http://lookuphost.com/bin/lookup.cgi?term=</xsl:text> MB> <xsl:apply-templates/> MB> </xsl:attribute> MB> <xsl:apply-templates/> MB> </A> I've tried to do the same but instead of A and HREF I was using OPTION and VALUE. And it didn't work. I wanted to transform <canal id="CP">Canal +</canal> into <option value="CP">Canal +</option> I'm using MSXML4 and this worked: <xsl:template match="canal"> <option> <xsl:value-of select="."/> </option> </xsl:template> But with this I only get: <option>Canal +</option> Then I tried to apply Mike's answer: <xsl:template match="canal"> <option> <xsl:attribute name="value"> <xsl:value-of select="@id"/> </xsl:attribute> <xsl:value-of select="."/> </option> </xsl:template> But it didn't work (the VBScript transformNode() method I'm using gave me a numeric error). This is what finally worked: <xsl:template match="canal"> <xsl:element name="option"> <xsl:attribute name="value"> <xsl:value-of select="@id"/> </xsl:attribute> <xsl:value-of select="."/> </xsl:element> </xsl:template> Why doesn't xsl:attribute works in the first try? Is it something specific from MSXML4? Thanks in advance and greetings from Spain Antonio http://www.webcsd.com mailto:atnbueno@xxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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