Re[2]: [xsl] simple method for listing directory contents?

["klaus e. werner" <vatidt04@xxxxxx>]

	Monday, 18 February 2002 at 10:39

	Deara Joerg,
	
	thanks for your tips!  I managed to get things done rather
	straightforward, using XML as the output format.
	
	klaus e. werner  |  vatidt04@xxxxxx

	From: Joerg Pietschmann <joerg.pietschmann@xxxxxx>
	To: XSL List <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
	Subject: Re: [xsl] simple method for listing directory contents?
	Date: Thu, 14 Feb 2002 15:32:20 +0100
	Message: <3C6BCA74.CA584A2E@xxxxxx>

|	"klaus e. werner" <vatidt04@xxxxxx> wrote:
|	> 	I know need to build a simple index file, with links to all the 500+
|	> 	docs and, if possible, references to their content ("title" and "date"
|	> 	would be enough).
|	
|	This is not really a XSL question, as XSL doesn't know anything
|	about files, directories or the file system.
|	
|	You could use a simple script (JavaScript, VB,...) which builds
|	a simple XML file
|	  <files>
|	    <file>foo.xml</file>
|	    <file>bar.xml</file>
|	   ...
|	  <files>
|	and process this with XSLT into the desired index page, perhaps
|	accessing title and some other data from the XML file referred to
|	with the document() function, or you could build an in-memory DOM
|	tree for instant use, or produce the desired HTML directly (less
|	recommended).
|	Looking up info in the FileSystemObject is useful for this task
|	if you want to do this from the IEx browser. Other tools, like
|	traditional Unix shells provided for example by Cygwin on the
|	windows plattform, have direct access to the file system.
|	
|	HTH
|	J.Pietschmann
|	
|	 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




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