Re: [xsl] Can I take only parts from node value?

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Re: [xsl] Can I take only parts from node value?

Subject: Re: [xsl] Can I take only parts from node value?
From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
Date: Tue, 19 Feb 2002 18:21:41 +0200

jp wrote:

<today date="200202190800" />

and I want output:

Time is 08:00 Date is 19.02 Year is 2002

How can I do this with XSL/T? Or should I change XML output?

Use substring(string, start, length?) function.

--
Oleg Tkachenko
Multiconn International, Israel

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Current Thread
[xsl] regd: XSLT in SAXON laksh vr - Tue, 19 Feb 2002 06:02:18 -0800 (PST) Michael Kay - Tue, 19 Feb 2002 14:25:00 -0000 jp - Tue, 19 Feb 2002 16:58:28 +0100 Robert Koberg - Tue, 19 Feb 2002 08:07:32 -0800 Oleg Tkachenko - Tue, 19 Feb 2002 18:21:41 +0200 <= Michael Kay - Tue, 19 Feb 2002 17:05:31 -0000 jp - Tue, 19 Feb 2002 18:27:56 +0100

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