Subject: RE: [xsl] embedded <xsl-for-each> From: "Andrew Welch" <awelch@xxxxxxxxxxxxxxx> Date: Thu, 21 Feb 2002 14:05:48 -0000 |
Hi, Which value are you after? As you use <xsl:for-each> to step through each /FLOW-MENU-GRP/FAMILY, and then a another <xsl:for-each> to step though each /FLOW-MENY-GRP/SERVICE, its not clear why you could not use position() on the 'service' elements to give you the same id number as that of the 'family' elements. If the number of each of type of element differs, what id number would you want then? If you post some sample data and the kind of result you are looking for, then your requirements will become clearer. cheers andrew === -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Sébastien Tisserant Sent: Thursday, February 21, 2002 1:24 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] embedded <xsl-for-each> hello i have this template: <xsl:template match="FLOW-MENU-GRP"> <xsl:for-each select="/FLOW-MENU-GRP/FAMILY"> <DIV> <xsl:attribute name="ID"><xsl:value-of select="position()"/></xsl:attribute> <xsl:value-of select="text()"/> </DIV> <xsl:for-each select="/FLOW-MENU-GRP/SERVICE"> <DIV> <xsl:attribute name="ID">here i'd like to get the value of position() given above in line 4</xsl:attribute> <xsl:value-of select="text()"/> </DIV> </xsl:for-each> </xsl:for-each></xsl:template> is this possible using and ancestor path? how should i write it? is this possible using <xsl:variable>? how should i use it? thanks sébastien XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list --- Incoming mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.325 / Virus Database: 182 - Release Date: 2/19/02 --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.325 / Virus Database: 182 - Release Date: 2/19/02 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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