|
Subject: [xsl] Omitting elements from output From: "Rick Quatro" <rick@xxxxxxxxxxxxxxx> Date: Fri, 22 Feb 2002 20:13:11 -0600 |
I have the follow structure in my stylesheet.
<xsl:template match="/">
<xsl:apply-templates/>
<xsl:template>
<xsl:template match="Element1">
...
</xsl:template>
<xsl:template match="Element2">
...
</xsl:template>
When I transform the XML file, I only want the content of Element1 and
Element2, but the content of the other elements is output as well. How do I
suppress the output of the other elements. Thanks.
Rick Quatro
Carmen Publishing
585 659-8267
rick@xxxxxxxxxxxxxxx
http://www.frameexpert.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Re: [xsl] getting a single quote in, Peter Davis | Thread | Re: [xsl] Omitting elements from ou, Joerg Heinicke |
| Re: [xsl] Omitting elements from ou, Joerg Heinicke | Date | RE: [xsl] Dynamically passing Param, Chris Bayes |
| Month |