| Subject: Re: [xsl] Resetting context to main document with "document()"? From: "Joerg Heinicke" <joerg.heinicke@xxxxxx> Date: Sat, 9 Mar 2002 00:08:49 +0100 | 
That's really a big stylesheet with many document()'s. Can't you remove one
or another template to see where the 'trash' comes from?
Here an example:
file1.xml
<xml>
    <node name="a">123</node>
    <node name="b">456</node>
    <node name="c">789</node>
</xml>
file2.xml
<xml>
    <nodes>
        <c/>
        <a/>
    </nodes>
</xml>
XSL
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
    <xsl:variable name="file1" select="/"/>
    <xsl:variable name="file2" select="document('file2.xml')"/>
    <xsl:template match="/">
        <xsl:for-each select="$file2/xml/nodes/*">
            <xsl:variable name="name" select="name()"/>
            <xsl:for-each select="$file1/xml">
                <xsl:value-of select="node[@name=$name]"/>
                <xsl:text>,</xsl:text>
            </xsl:for-each>
        </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>
Output:
789,123,
No trash, only the expected output. Maybe this helps a bit.
Joerg
> Hi Joerg,
> here is the stylesheet - in order to properly test it I would need to send
> you also the xml files etc. If necessary, I can send the whole set.
> The problem is that when I set the variable to "/", it outputs as an error
> message words from the "templates" file (what I interpreted as trash...),
> complaining "is not a valid URL".
> Now I fixed it passing the same pathname twice to the xsl processor, once
> as the name of the parsed file and once as a simple parameter. Not
elegant,
> isn't it?
> Thank you very much,
> Costantino
> <xsl:variable name="doc" select="/"/> is THE one and in any case best
> solution to handle this problem. That MSXML outputs trash is not standard,
> it must come from your stylesheet. You can post your complete stylesheet
> here and we will have a look at it.
>
> Regards,
>
> Joerg
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