|
Subject: Re: [xsl] Key function using key strings from msxsl:node-set generated node. Doesn't work? From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Fri, 15 Mar 2002 10:49:10 +0000 |
Hi Gennady,
> Actually it gives Person by Address node-set, not a string. If you
> use this key, you must supply an Address **element**, which is a
> child of the Person element you are looking for. You are supplying a
> string and therefore getting nothing (as it should be).
That's not exactly true. If the expression that you use in the use
attribute of xsl:key evaluates to a node set, then you get a number of
entries for the matched node, one for each node in the node set. The
*value* for these keys is still a string value, just a string value of
the node.
So in:
<xsl:key name="PersonByAddress" match="/People/Person"
use="Address" />
then given that each Person has just one Address, the use attribute
returns a single Address element. The Person element's key value is
the string value of that Address element. It's exactly the same as
defining the key as:
<xsl:key name="PersonByAddress" match="/People/Person"
use="string(Address)" />
Likewise, when you access a key with the key() function, the second
argument always gets converted to a string. There's no need to make
sure that the two expressions (when defining the key and when using
the key) have the same object type.
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| RE: [xsl] Key function using key st, Gennady Loskutov | Thread | [xsl] XML Varaible scope problem, tunuguntla srinivas |
| Re: [xsl] Key function using key st, Jeni Tennison | Date | RE: [xsl] javascript problem----- I, stevenson |
| Month |