Re: [xsl] commandline parameters

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

On the page http://xml.apache.org/xalan-j/commandline.html you can see 
the correct syntax:

java org.apache.xalan.xslt.Process -IN foo.xml -XSL foo.xsl -OUT foo.out 
  -PARAM name value

In your stylesheet you have to set a top-level-param:


> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:param name="commandparam" value="'default'"/>

> <xsl:template match="/">

You don't need <xsl:param> here.

>     <xsl:value-of select="$commandparam"/>
> </xsl:template>
> </xsl:stylesheet>
>
>
> My questions are:
> 1. If i want to read the parameter through -PARAM, is the above xsl 
> correct?
> 2. what would be the command that runs in the commandline to pass on the 
> parameter. would it be something like this..
>   java org.apache.xalan.xslt.Process -IN commandlineexp.xml
> -XSL commandlineexp.xsl -OUT multi -PARAM commandparam commandparamvalue?
>
> please let me know if i am wrong and in that case the correct syntax of 
> the commandline statement and the xsl structure
> laura

Regards,

Joerg

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