Subject: RE: [xsl] Finding Unique Nodes From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Tue, 2 Apr 2002 10:14:12 +0100 |
> I have a list of items, many with duplicate values. I'd like > to identify > only those that are unique. > > For example: > > <list> > <item>Apple</item> > <item>Apple</item> > <item>Apple</item> > <item>Apple</item> > <item>Orange</item> > <item>Pear</item> > <item>Pear</item> > <item>Pear</item> > </list> > > > <xsl:value-of select="count(list/items)"/> > > The above XML has 8 entries but I only want to tally those > that are unique-- > 3. For general advice on grouping, see www.jenitennison.com/xslt/grouping For this particular case, the simplest solution is count(list/item[not(.=preceding-sibling::item)]) Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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