RE: [xsl] For each loop faliure

[Jarno.Elovirta@xxxxxxxxx]

Correction,

> -----Original Message-----
> From: Elovirta Jarno (NBI/Espoo) 
> Sent: 05. April 2002 11:08
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] For each loop faliure
> 
> 
> Heppa,
> 
> > In the below code I want to for loop to be continued for all nodes.
> > 
> > But here in this code below in the first case itself if the 
> > condition fails
> > it goes out of for each loop.
> > 
> > How about to proceed?
> > 
> > <xsl:for-each select="$A/RecipeVersions">
> > 		<xsl:for-each select="$B/RecipeVersions">
> > 			<xsl:if 
> > test="($A/RecipeVersions/RecipeVersion/VersionID !=
> > $B/RecipeVersions/RecipeVersion/VersionID) = false">
> 
> this should be
> 
>   <xsl:if test="$A/RecipeVersions/RecipeVersion/VersionID = 
> $B/RecipeVersions/RecipeVersion/VersionID">

It should be of course be

  <xsl:for-each select="$A/RecipeVersions">
    <xsl:variable name="outer-loop" select="." />
    <xsl:for-each select="$B/RecipeVersions">
      <xsl:if test="$outer-loop/RecipeVersion/VersionID = RecipeVersion/VersionID">
        <xsl:value-of select="RecipeVersion/VersionID"/>
      </xsl:if>
     </xsl:for-each>
  </xsl:for-each>

Santtu

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