Subject: Re: [xsl] Ignoring default attributes during XSL transform From: Manny Parasirakis <mannyp@xxxxxxx> Date: Thu, 18 Apr 2002 09:51:37 -0400 |
Thank You, Manny
As far as I know, the default value (from DTD) of attributes are added by the parser (please correct me if I'm wrong). So when the stylesheet gets the document, every attribute is in the XML tree. But the stylesheet knows nothing about whether it's a default value - the attribute is in the tree, not more, not less.
Regards,
Joerg
Manny Parasirakis wrote:My follow on question is whether or not there is a way to compare an attribute value to its default value defined in the DTD?
At 10:02 PM 4/17/2002 +0200, Joerg Heinicke wrote:
<xsl:apply-templates select="* | @*[. != '']">
Regards,
Joerg
Manny Parasirakis wrote:
I am trying to figure out how I can ignore outputting attributes whose values are not set (=""). I am fairly new at this but cannot figure it out. I need to do this for all XML tags. Here is my XSL:
<xsl:template match="*|@*">
<xsl:copy>
<xsl:apply-templates select="*|@*"/>
</xsl:copy>
</xsl:template>
I've tried a bunch of things but cannot figure this out.
--
System Development VIRBUS AG Fon +49(0)341-979-7419 Fax +49(0)341-979-7409 joerg.heinicke@xxxxxxxxx www.virbus.de
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