Subject: Re: [xsl] incrementing a counter in XSL From: becky.foley@xxxxxxxxxxxxxx Date: Fri, 19 Apr 2002 09:39:01 -0400 |
Thanks! This worked much better. Thanks Wendell for the other option as well. Greg Faron <gfaron@xxxxxxxxxxxxxxxxxx>@lists.mulberrytech.com Thursday April 18, 2002 03:12 PM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx Sent by: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx cc: Subject: Re: [xsl] incrementing a counter in XSL At 12:05 PM 4/18/2002, you wrote: >I am selecting some nodes from an XML doc with an if statment in a for-each >loop. Out of the set of nodes I am looping through, I am only selecting >some in the if statment. Each of these nodes that is selected by the if >statement needs a sequence number. Originally I was using : > <xsl:for-each select="Contract/TermRdr"> > <xsl:if test="StatusCd='A' or StatusCd='F'"> > <SequenceNum fieldType="Short" elementType="field"> > <xsl:number value ="position()"/> > </SequenceNum> > .... > </xsl:if> > </xsl:for-each> First, don't try to implement a counter. There's a different way to do it in the XSLT mindset. Assuming that the provided xsl:if is the only test that you perform for each run through the xsl:for-each loop (I assume this due to the position of the ellipses), you can select your exact nodes during the xsl:for-each and forget about the xsl:if. <xsl:for-each select="Contract/TermRdr[StatusCd='A' or StatusCd='F']"> <SequenceNum fieldType="Short" elementType="field"> <xsl:number value ="position()"/> </SequenceNum> .... </xsl:for-each> position() gives the position of the current element in relation to the others of the selected node-set, not the absolute value from the document order. Greg Faron Integre Technical Publishing Co. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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