Subject: RE: [xsl] last(): selecting the last one? From: Jarkko.Moilanen@xxxxxx Date: Mon, 22 Apr 2002 14:50:19 +0300 (EEST) |
The situation is a bit more complex than that and I did not express my self clearly.... The sorting is done by this kind of syntax: Sort the topics by date and then sort by clocktime. The final soring is done by the topic. (actually the sorting is more complex, but this here needs so far)So the message order is actually like this: message0 11.10.2001 05:56 topic:harjoitus message1 12.10.2001 09:45 topic:re:harjoitus message2 13.10.2001 06:23 topic:re:harjoitus message3 12.10.2001 11:34 topic:kysmys message4 12.10.2001 12:45 topic:re:kysmys and so on... > > > when xml-file contains several elements (information)and they > > have element which > > tells the date of input and then there is element that tells the > > clock time of input and another element called subject. > > > > How can I find out which one is the last one and > > then select it's subject elements content? > > Sort them by date and time (in that order) and then select the > position() = last(). So, if I sort them by that, the order is broken. Can this be done by using some kind of idea like: check the attribute values time and clock (in that order) and select the one which has "highest value" in both of them? Cheers Jarkko ******************************************************************* Jarkko Moilanen *You are wise, witty, and wonderful, * Researcher/ ITCM *but you spend too much time * jarkko.moilanen@xxxxxx *reading this sort of trash. * www.uta.fi/~jm60697 * * GSM: +358 50 3766 927 * * ******************************************************************* * ITCM Information Technology and Crisis Management * ******************************************************************* XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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