Subject: Re: [xsl] xalan:nodeset or xsl:copy-of problem From: Ming <myu@xxxxxxxx> Date: Tue, 23 Apr 2002 16:59:36 -0600 |
Hi, Greg, I've tried both but it still won't work. Really confused about this problem. Ming Greg Faron wrote: > At 04:24 PM 4/23/2002, you wrote: > > <xsl:variable name="nodetree"> > > <xsl:for-each select="$full_path[contains($dbs_searched,@db)]"> > ><!-- $dbs_searched variable is passed from a different stylesheet --> > > <xsl:copy-of select="."/> > > </xsl:for-each> > > </xsl:variable> > > This isn't a solution to your problem (still thinking about it though) > but it might help your readability/efficiency. I read on topxml.com the > following about copy-of: > Copies a full tree including attributes to the destination > document. If multiple nodes are matched by the select attribute, > they are all copied. > > This would change the above variable declaration to the following: > <xsl:variable name="nodetree"> > <xsl:copy-of select="$full_path[contains($dbs_searched,@db)]"/> > </xsl:variable> > > In the past, I've created a second temporary variable to hold the > nodeset'ed version. You might try that as well. > > <xsl:variable name="nodetree2" select="xalan:nodeset($nodetree)" /> > > Greg Faron > Integre Technical Publishing Co. > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list -- Ming Yu Library Without Walls Team Research Library, MS P362 Los Alamos National Laboratory Los Alamos, NM 87545 Voice: 505-665-0102 Fax: 505-665-6452 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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