Subject: [xsl] Re: RE: Finding corresponding node in structurally identical sibling tree? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Fri, 26 Apr 2002 10:28:09 -0700 (PDT) |
Oooppsss.... I wrote: > <xsl:variable name="br1AncIndex" > select="$br1/count(ancestor::node())"/> > ...... > <xsl:variable name="br2AncIndex" > select="$br2/count(ancestor::node())"/> must be: > <xsl:variable name="br1AncIndex" > select="count($br1/ancestor::node())"/> > ...... > <xsl:variable name="br2AncIndex" > select="count($br2/ancestor::node())"/> Cheers, Dimitre Novatchev. __________________________________________________ Do You Yahoo!? Yahoo! Games - play chess, backgammon, pool and more http://games.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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