Subject: Re: [xsl] xsl:sort question From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Fri, 26 Apr 2002 20:15:12 +0200 |
<xsl:sort select="substring(@WellName,1,1)"/> <xsl:sort select="substring(@WellName,2)" data-type="number"/>
I am not getting the above result with my XSL. What is the problem ? <xsl:template match="ANALYSISRESULTS"> <xsl:variable name="wells" select="//WELL"/> <xsl:for-each select="$wells"> <xsl:sort select="@WellName"/> <xsl:sort select="substring(@WellName,2)" data-type="number"/> <xsl:for-each select="@*"> <xsl:value-of select="."/> <xsl:value-of select="$tab"/> </xsl:for-each> <xsl:value-of select="$newline"/> </xsl:for-each> </xsl:template>
Thanks, Priya X 323
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] xsl:sort question, Sripriya Venkatarama | Thread | RE: [xsl] xsl:sort question, Sripriya Venkatarama |
Re: [xsl] Match pattern should get , Thomas B. Passin | Date | Re: [xsl] pdf-bookmarks with xsl fo, G. Ken Holman |
Month |