RE: [xsl] problem in using * as a default parameter in xsl:param

[TSchutzerWeissmann@xxxxxxxxxxxxxxxx]

Michael Kay wrote:

><xsl:param name="childElement" select="'*'"/>
>
><xsl:for-each
>   select="element[$childElement!='*][childName=$childElement] |
>           element[$childElement='*']">
>

Michael, Oleg,

This is an elegant way of making * into a wildcard, but won't it test the
text value of the children rather than their name?

If one was to use this, 
	select="element/*[local-name()=$childElement]", as Oleg suggests,
will * then act as a wildcard anyway?

Thanks for your help,
Tom

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